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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A man travels 1 km east , then 5 km due south , then 2 km due east and finally 9 km due north. How far is he from the starting point ?

$\begin{array}{1 1}(A)\;3\;km \\(B)\;5\;km \\(C)\;4\;km\\(D)\;6\;km \end{array} $

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1 Answer

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$ \overrightarrow {S}= \overrightarrow{S_1}+\overrightarrow{S_2}+\overrightarrow{S_3}+\overrightarrow{S_4}$
$\qquad=(i) +(-5j) +(2i) +(9j) $
$\qquad= 3i+4j$
$| \overrightarrow {S}|=\sqrt {(3)^2 +(4)^2}= 5 km$
Hence B is the correct answer.
answered Jul 16, 2014 by meena.p

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