Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Caesium chloride may be considered to form interpenetrating simple primitive cubic crystals.The edge length of unit cell is 412pm.Determine the density of CsCl.Given :M(Cs)=$133gmol^{-1}$

$\begin{array}{1 1}4.0gcm^{-3}\\3.0gcm^{-3}\\4.2gcm^{-3}\\2.0gcm^{-3}\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : $4.0gcm^{-3}$
The interpenetrating simple primitive cubic crystals means the unit cell is body-centred where $Cl^-$ ions occupy corners and $Cs^+$ ion occupy body centre of the cube.There is one $Cs^+$ ion and one $Cl^-$ ( or one molecule of CsCl) per unit cell.
From the expression
$\rho=\large\frac{1}{(412\times 10^{-12}m)^3}\big(\frac{168.5gmol^{-1}}{6.023\times 10^{23}mol^{-1}}\big)$$=0.4\times 10^7gm^{-3}=4.0gcm^{-3}$
answered Jul 16, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App