$\begin{array}{1 1}(9/8)mol\\(5/4)mol\\(3/4)mol\\(6/5)mol\end{array} $

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Answer : (9/8) mol

Let there be 1 mol of iron atom.we will have

Amount of Fe(III)=(1/4) mol

Amount of Fe(II)=(3/4) mol

Total positive charges =1 mol/4)(3)+(3 mol/4)(2)=(9/4) mol

Let $x$ be the amount of oxygen atoms,we have

Total negative charges =x(2)

To satisfy electrical neutrality,we have

Total positive charges=Total negative charges

$\large\frac{9}{4}$ mol=$2x$

$x=(9/8)$ mol

Hence the composition of the composition is $FeO_{9/8}$ or $Fe_8O_9$

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