$\begin{array}{1 1}1.36\\1.26\\1.46\\1.16\end{array} $

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Answer : 1.26

The expression of density is

$\rho =\large\frac{N}{a^3}\big(\frac{M}{N_A}\big)$

For face-centred cubic unit cell,N=4.For body-centred cubic unit cell,N=2

Hence,$\large\frac{\rho_{FCC}}{\rho_{BCC}}=\frac{N_{FCC}a^3_{BCC}}{a^3_{FCC}N_{BCC}}=\frac{4}{(3.5A^{\large\circ})^3}\frac{(3.0A^{\large\circ})^3}{2}$$=1.26$

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