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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
+1 vote

Three vectors $\overrightarrow{A},\overrightarrow{B} $ and $ \overrightarrow{C}$ satisfy the relation $\overrightarrow{A}.\overrightarrow{B}= 0$ and $\overrightarrow{A}.\overrightarrow{C}=0$ Vector $\overrightarrow{A}$ is parallel to

$\begin{array}{1 1}(A)\;\overrightarrow{B} \\(B)\;\overrightarrow{C} \\(C)\;\overrightarrow{B}.\overrightarrow{C} \\(D)\;\overrightarrow{B} \times \overrightarrow{C} \end{array} $

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1 Answer

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Since $\overrightarrow{A}.\overrightarrow{B}=0$ So, $\overrightarrow{A} \perp \overrightarrow{B}$.
Also, $\overrightarrow{A}.\overrightarrow{C}=0$ ,So $\overrightarrow{A} \perp \overrightarrow{C}$.
Hence $\overrightarrow{A} $ is normal to the plane containing $\overrightarrow{B}$ and $\overrightarrow{C}$ .
Since $\overrightarrow{B} \times \overrightarrow{C}) $ represents a vector normal to the plane containing $\overrightarrow{B}$ and $\overrightarrow{C}$ So $\overrightarrow{A}$ is parallel to $(\overrightarrow{B} \times \overrightarrow{C}) $.
Hence D is the correct answer.
answered Jul 17, 2014 by meena.p

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