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An azeotropic solution of two liquid s has a boiling point lower than either of them when it

$\begin{array}{1 1}\text{shows negative deviation from Raoult's law}\\\text{shows no deviation from Raoult's law}\\\text{shows positive deviation from Raoult's law}\\\text{is saturated}\end{array}$

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Answer : shows positive deviation from Raoult's law
Positive deviation from Raoult's law implies higher vapour pressure and thus lower boiling point
answered Jul 17, 2014 by sreemathi.v
 

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