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The freezing point of equimolal aqueous solutions will be highest for

$\begin{array}{1 1}C_6H_5NH_3Cl(anilinium\; chloride)\\Ca(NO_3)_2\\La(NO_3)_3\\C_6H_{12}O_6(glucose)\end{array} $

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Answer : $C_6H_{12}O_6$(glucose)
Glucose being nonelectrolyte produces lesser value of $-\Delta T_f$ and hence higher freezing point.
answered Jul 17, 2014 by sreemathi.v

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