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The expression relating molarity (M) and molality (m) of a solution is (where $\rho$ is the density of solution and $M_2$ is the molar mass of solute)

$\begin{array}{1 1}m=\large\frac{M}{\rho+MM_2}\\m=\large\frac{M}{\rho-MM_2}\\m=\large\frac{\rho+MM_2}{M}\\m=\large\frac{\rho-MM_2}{M_2}\end{array} $

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Answer : $m=\large\frac{M}{\rho-MM_2}$
$\Rightarrow \large\frac{n_2}{\rho V-n_2M_2}=\frac{n_2/V}{\rho-(n_2/V)M_2}=\frac{M}{\rho-MM_2}$
answered Jul 17, 2014 by sreemathi.v

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