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# For a dilute solution containing a nonvolatile solute,the molar mass of solute evaluated from the elevation of boiling point is given by the expression

$\begin{array}{1 1}M_2=\large\frac{\Delta T_b}{K_b}\frac{m_1}{m_2}\\M_2=\large\frac{\Delta T_b}{K_b}\frac{m_2}{m_1}\\M_2=\large\frac{K_b}{\Delta T_b}\frac{m_2}{m_1}\\M_2=\large\frac{K_b}{\Delta T_b}\frac{m_1}{m_2}\end{array}$

Answer : $M_2=\large\frac{K_b}{\Delta T_b}\frac{m_2}{m_1}$
$\Delta T_b=K_b m=K_b\large\frac{n_2}{m_1}=$$K_b\large\frac{(m_2/M_2)}{m_1}$
Hence,$M_2=\large\frac{K_b}{\Delta T_b}\frac{m_2}{m_1}$