logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

For a dilute solution containing a nonvolatile solute,the molar mass of solute evaluated from the osmotic pressure measurement is given as

$\begin{array}{1 1}M_2=\large\frac{m_2}{V}\frac{RT}{\Pi}\\M_2=\large\frac{m_2}{V}\frac{\Pi}{RT}\\M_2=m_2\large\frac{RT}{\Pi}\\M_2=m_2\large\frac{\Pi}{RT}\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Answer : $M_2=\large\frac{m_2}{V}\frac{RT}{\Pi}$
We have
$\Pi=cRT=\large\frac{n_2}{V}$$RT=\large\frac{(m_2/M_2)}{V}$$RT$
Hence,$M_2=\large\frac{m_2}{V}\frac{RT}{\Pi}$
answered Jul 17, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...