Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If one molecule of an electrolyte dissociates to produce $v_+$ number of cations $A^{z+}$ and $v_-$ number of anions $B^{z-}$,then the relation between molar conductivity $(\Lambda_m)$ and equivalent conductivity $(\Lambda_{eq})$ is

$\begin{array}{1 1}\Lambda_m=(v_+z_+)\Lambda_{eq}\\\Lambda_m=\Lambda_{eq}(v_+z_+)\\\Lambda_m=v_+\Lambda_{eq}/z_+\\\Lambda_m=z_+\Lambda_{eq}/v_+\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : $\Lambda_m=(v_+z_+)\Lambda_{eq}$
The relation connecting molar and equivalent conductivities is $\Lambda_m=(v_+z_+)\Lambda_{eq}$
answered Jul 18, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App