Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Equivalent conductivity of $Fe_2(SO_4)_3$ is related to molar conductivity by the expression

$\begin{array}{1 1}\Lambda_{eq}=\Lambda_m\\\Lambda_{eq}=\Lambda_m/3\\\Lambda_{eq}=3\Lambda_m\\\Lambda_{eq}=\Lambda_m/6\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : $\Lambda_{eq}=\Lambda_m/6$
Since total charge of cations is 6+ in $Fe_2(SO_4)_3$,we have
answered Jul 18, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App