Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The standard reduction potentials,$E^{\large\circ}$,for the half reactions are $Zn^{2+}+2e^-=Zn,E^{\large\circ}=-0.76V$ and $Fe^{2+}+2e^-=Fe,E^{\large\circ}=-0.41V$.The emf of the cell involving the reaction $Fe^{2+}+zn\rightarrow Zn^{2+}+Fe$ is

$\begin{array}{1 1}-0.35V\\1.17V\\0.35V\\-1.17V\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : 0.35V
In the given reaction Zn is oxidised to $Zn^{2+}$ and $Fe^{2+}$ is reduced to Fe.Hence,
answered Jul 18, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App