By how much will the potential of half-cell $Cu^{2+}|Cu$ change if the solution is diluted to 100 times at 298K?

$\begin{array}{1 1}\text{Increases by 59mV}\\\text{Decreases by 59mV}\\\text{Increases by 29.5mV}\\\text{Decreases by 29.5mV}\end{array}$

For the reaction $Cu^{2+}+2e^-\rightarrow Cu$,Nernst equation is
$E=E^{\large\circ}-\large\frac{RT}{2F}$$\ln \large\frac{1}{[Cu^{2+}]} If the solution is diluted 100 times,then we have E_2-E_1=-\large\frac{RT}{2F}$$\ln \large\frac{[Cu^{2+}]}{(0.01)[Cu^{2+}]}$
$\Rightarrow \large\frac{RT}{2F}$$\ln(0.01)=-\large\frac{2\times 0.059V}{2}$$=-0.059V$