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A galvanic cell which makes use of the following reaction at 298K. $Cr_2O_7^{2-}+14H^++6Fe^{2+}\rightarrow 2Cr^{3+}+6Fe^{3+}+7H_2O$.Given : $E^{\large\circ}(Cr_2O_7^{2-},H^+,Cr^{3+}|Pt)=1.33V;E^{\large\circ}(Fe^{3+},Fe^{2+}|Pt)=0.77V$.The cell emf depends on

$\begin{array}{1 1}\text{size of anode}\\\text{size of cathode}\\\text{volume of solution}\\\text{temperature}\end{array} $

1 Answer

Answer : temperature
The emf of the cell will depends on temperature through Nernst equation
$E=E^{\large\circ}-\large\frac{RT}{6F}$$\ln \large\frac{[Cr^{3+}]^2[Fe^{3+}]^6}{[Cr_2O_7^{2-}][H^+]^{14}[Fe^{2+}]^6}$
answered Jul 21, 2014 by sreemathi.v

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