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A galvanic cell which makes use of the following reaction at 298K. $Cr_2O_7^{2-}+14H^++6Fe^{2+}\rightarrow 2Cr^{3+}+6Fe^{3+}+7H_2O$.Given : $E^{\large\circ}(Cr_2O_7^{2-},H^+,Cr^{3+}|Pt)=1.33V;E^{\large\circ}(Fe^{3+},Fe^{2+}|Pt)=0.77V$.The strongest oxidant is

$\begin{array}{1 1}Cr_2O_7^{2-}\\Fe^{2+}\\Cr^{3+}\\Fe^{3+}\end{array} $

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Answer : $Cr_2O_7^{2-}$
The strongest oxidant is $Cr_2O_7^{2-}$ as it oxidises $Fe^{2+}$ and $Fe^{3+}$
answered Jul 21, 2014 by sreemathi.v
 

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