logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Electrochemistry

A galvanic cell which makes use of the following reaction at 298K. $Cr_2O_7^{2-}+14H^++6Fe^{2+}\rightarrow 2Cr^{3+}+6Fe^{3+}+7H_2O$.Given : $E^{\large\circ}(Cr_2O_7^{2-},H^+,Cr^{3+}|Pt)=1.33V;E^{\large\circ}(Fe^{3+},Fe^{2+}|Pt)=0.77V$.The strongest reductant is

$\begin{array}{1 1}Cr_2O_7^{2-}\\Fe^{2+}\\Cr^{3+}\\Fe^{3+}\end{array} $

1 Answer

Answer : $Fe^{2+}$
The strongest reductant is $Fe^{2+}$ as it reduces $Cr_2O_7^{2-}$
answered Jul 21, 2014 by sreemathi.v
 

Related questions

Download clay6 mobile appDownload clay6 mobile app
...
X