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The following facts are available.\[\begin{array}{1 1}2X^-+Y_2\rightarrow 2Y^-+X_2\\2W^-+Y_2\rightarrow\text{No reaction}\\2Z^-+X_2\rightarrow 2X^-+Z_2\end{array}\] Which of the following statements is correct?

$\begin{array}{1 1}E^{\large\circ}_{W-|W_2} > E^{\large\circ}_{Y-|Y_2} > E^{\large\circ}_{X-|X_2} > E^{\large\circ}_{Z-|Z_2}\\E^{\large\circ}_{W-|W_2} < E^{\large\circ}_{Y-|Y_2} < E^{\large\circ}_{X-|X_2} < E^{\large\circ}_{Z-|Z_2}\\E^{\large\circ}_{W-1W_2} < E^{\large\circ}_{Y-|Y_2} > E^{\large\circ}_{X-|X_2} > E^{\large\circ}_{Z-|Z_2}\\E^{\large\circ}_{W-|W_2} > E^{\large\circ}_{Y-|Y_2} < E^{\large\circ}_{X-|X_2} < E^{\large\circ}_{Z-|Z_2}\end{array} $

1 Answer

Answer : $E^{\large\circ}_{W-|W_2} > E^{\large\circ}_{Y-|Y_2} > E^{\large\circ}_{X-|X_2} > E^{\large\circ}_{Z-|Z_2}$
From the first reaction,we conclude $E_{Y-|Y_2} > E_{X-|X_2}$
From the first reaction,we conclude $E_{W-|W_2} > E_{Y-|Y_2}$
From the third reaction,we conclude $E_{X-|X_2} > E_{Z-|Z_2}$
Hence,$E^{\large\circ}_{W-|W_2} > E^{\large\circ}_{Y-|Y_2} > E^{\large\circ}_{X-|X_2} > E^{\large\circ}_{Z-|Z_2}$
answered Jul 21, 2014 by sreemathi.v
How do we make these conclusions?
Is it because the one getting reduced has higher reduction potential?
 

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