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Adding powdered Pb and Fe to a solution containing 1.0M in each of $Pb^{2+}$ and $Fe^{2+}$ ions would result into the formation of

$\begin{array}{1 1}\text{more of Pb and }Fe^{2+}\text{ ions}\\\text{more of Fe and }Pb^{2+}\text{ ions}\\\text{more of Fe and Pb}\\\text{more of }Fe^{2+}\text{ and }Pb^{2+}\text{ ions}\end{array} $

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Answer : $\text{more of Pb and }Fe^{2+}\text{ ions}$
Since $E^{\large\circ}_{Pb^{2+}|Pb}$ is less negative,$Pb^{2+}$ has more tendency to reduce as compared to $Fe^{2+}$.Hence $Pb^{2+}$ will be reduced to Pb and Fe will be oxidised to $Fe^{2+}$ .Thus,more of Pb and $Fe^{2+}$ are formed.
answered Jul 22, 2014 by sreemathi.v

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