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What mass of ethanol be added to 1.0Kg water to have the mole fraction of ethanol equal to 0.20?

$\begin{array}{1 1}63.89g\\6.39g\\638.89g\\683.89g\end{array} $

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Answer : 638.89g
$\Rightarrow \large\frac{m}{46g}=\frac{0.2\times 1000}{18}\times \frac{1}{0.8}$$=13.89$
$m=13.89\times 46g=638.89g$
answered Jul 22, 2014 by sreemathi.v

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