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# The vapour-pressure lowering of a solvent is proportional to

$\begin{array}{1 1}\text{the mole fraction of the solute}\\\text{the mole fraction of the solvent}\\\text{the molality of the solvent}\\\text{the normality of the solution}\end{array}$

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Answer : the mole fraction of the solute
The vapour-pressure lowering of a solvent is proportional to the mole fraction of the solute
answered Jul 22, 2014