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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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The vapour-pressure lowering of a solvent is proportional to

$\begin{array}{1 1}\text{the mole fraction of the solute}\\\text{the mole fraction of the solvent}\\\text{the molality of the solvent}\\\text{the normality of the solution}\end{array} $

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