Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

A binary solution contains 4 mol of A and 6 mol of B.Its vapour pressure is found to be 460mm Hg.To this solution,when 10 mol of B is added,its vapour pressure becomes 480mm Hg.The vapour pressures of pure A and pure B,respectively,are

$\begin{array}{1 1}\text{300 mmHg,600 mmHg}\\\text{400 mmHg and 500 mmHg}\\\text{300 mmHg,500 mmHg}\\\text{400 mmHg and 600 mmHg}\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : 400 mmHg and 500mmHg
Initially,mole fractions of A and B in liquid solutions are 0.4 and 0.6 respectively.The addition of 10 mol of B changes mole fraction to 0.2 and 0.8 respectively.With these mole fractions,$p_A^*$ and $p_B^*$ are 400mmHg and 500mmHg respectively.
answered Jul 22, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App