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The reaction occuring at anode when the electrolysis of $CuSO_4$ is done using Pt electrode,is

$\begin{array}{1 1}Cu\rightarrow Cu^{2+}+2e^-\\2SO_4^{2-}+2H_2O\rightarrow H_2SO_4+O_2+4e^-\\2H_2O\rightarrow O_2+4H^++4e^-\\2Cu\rightarrow Cu_2^{2}++2e^-\end{array} $

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Answer : $2H_2O\rightarrow O_2+4H^++4e^-$
Anodic reaction is $2H_2O\rightarrow O_2+4H^++4e^-$
answered Jul 23, 2014 by sreemathi.v

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