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In the electrolysis of alkaline water,a total of 1 mol of gases is evolved.The amount of water decomposed would be

$\begin{array}{1 1}\text{1 mol}\\\text{2 mol}\\\text{(1/3) mol}\\\text{(2/3) mol}\end{array} $

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Answer : (2/3) mol
The overall decomposition reaction is $2H_2O\rightarrow 2H_2O+O_2$
The amount of water decomposed is (2/3) mol.
answered Jul 23, 2014 by sreemathi.v
 

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