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Which of the following does not evolve oxygen at anode when the electrolysis is carried out of

$\begin{array}{1 1}\text{dilute }H_2SO_4\text{ with Pt electrodes}\\\text{fused sodium hydroxide with Pt electrodes}\\\text{acidic water with Pt electrodes}\\\text{dilute sulphuric acid using Cu electrodes}\end{array} $

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Answer : dilute sulphuric acid using Cu electrodes
In the electrolysis of dilute $H_2SO_4$ using Cu electrodes,the reaction occurring at anode is $Cu\rightarrow Cu^{2+}+2e^-$
answered Jul 23, 2014 by sreemathi.v
 

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