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The structure of $SF_4$ is

$\begin{array}{1 1}\text{square planar}\\\text{tetrahedral}\\\text{trigonal bipyramidal}\\\text{octahedral}\end{array} $

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Answer : trigonal bipyramidal
The hybridization of S in $SF_4$ is $sp^3d$.Hence it is trigonal bipyramidal
answered Jul 23, 2014 by sreemathi.v
 
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