logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The radii of F, O, F$^{-}$ and O$^{2-}$ follows which of the following orders:

$\begin{array}{1 1} F < O < F^{-} < O^{2-} \\ F^{-} < O^{2-} < F < O \\ F < F^{-} < O < O^{2-} \\ O < O^{2-} < F < F^{-} \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Answer: F < O < F$^{-}$ < O$^{2-}$
Across a period, atomic radius decreases, the radius of F is less than the radius of O.
O$^{2-}$ and F$^{-}$ are isoelectronic ions $\rightarrow$ their ionic radis is inversely propotional to the effective nuclear charge.
$\Rightarrow r_{F^{-}} \lt r_{O^{2-}}$
Therefore the correct order is F < O < F$^{-}$ < O$^{2-}$
answered Jul 23, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...