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Silver bromide is soluble in sodium thiosulphate due to the formation of the complex

$\begin{array}{1 1}Na [ Ag(S_2O_3) ] \\ Na_3 [ Ag(S_2O_3)_2 ] \\Na_5 [ Ag(S_2O_3)_3 ] \\Na_7 [ Ag(S_2O_3)_4 ] \end{array} $

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Answer : $Na_5 [ Ag(S_2O_3)_3 ]$
Solubility of AgBr in $Na_2S_2O_3$ is due to the formation of the complex $Na_5 [ Ag(S_2O_3)_3 ]$
answered Jul 24, 2014 by sreemathi.v
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