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Which of the following compounds is the most polar: H$_2$O (l), H$_2$S (g), HF (l), HCl (g) ?

$\begin{array}{1 1} HF(1) \\ H_2S(g) \\ H_2O\;(l)\\ HCl(g) \end{array}$

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Answer: HF (l)
All the compounds given above contain one element same that is hydrogen and its electronegativity is 2.20.
We should then consider the electronegativity of the other elements which is as follows:
$\begin{array} {llll} F & O & Cl & S\\ 3.98 & 3.44 & 3.16 & 2.56 \\ \end {array}$
The most electronegative element is fluorine. So, the electronegativity difference in HF is the most $\rightarrow$ HF(g) is the most polar.
answered Jul 24, 2014 by balaji.thirumalai
edited Jul 24, 2014 by balaji.thirumalai
 

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