Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The thermal decomposition of N$_2$O$_5$ to form NO$_2$ and O$_2$ is a first order reaction. The rate constant for the reaction is $5.1x10^{–4}s^{-1}$ at $318^{\circ} K$. Calculate the half-life of this reaction.

$\begin{array}{1 1} 1400\;s \\ 2800 \;s \\ 700\;s \\ 2100\;s \end{array}$

Can you answer this question?

1 Answer

0 votes
Answer: 1400 s
The half life $t_{1/2} = \large\frac{ ln\;2}{k}$$ = \large\frac{0.693}{k}$.
$\Rightarrow = \large\frac{0.693}{5.1x10^{–4}s^{-1}}$$ = 1400\;s$
answered Jul 24, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App