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Hydrolysis of $SiF_4$ in alkaline medium produces

$\begin{array}{1 1}SiO_2\\H_2SiO_4\;and\;H_2SiF_6\\H_2SiF_6\\H_2SiO_4\;and\;SiO_2\end{array} $

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Answer : $H_2SiO_4$ and $H_2SiF_6$
$SiF_4+4H_2O\rightarrow Si(OH)_4+4HF$ and $SiF_4+2HF\rightarrow 2H^++[SiF_6]^{2-}$
answered Jul 25, 2014 by sreemathi.v
 
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