Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If $[A] = 55\;M$ at $39s$, $[A]_o = 99\;M$, and $[B]_o = 1000\;M$, what is the 2nd order reaction rate constant?

Can you answer this question?

1 Answer

0 votes
Answer: $k' =1.507 \times 10^{-5}M^{-1}s^{-1}$
Given $[A] = 55\;M$ at $39s$, $[A]_o = 99\;M$, and $[B]_o = 1000\;M$.
Since $[B]_0 \gt \gt [A]_0$ we can treat this as a pseudo-first order reaction.
We can use the rate equation $[A] = [A]_0 e^{-k't[B]_0}$
$\Rightarrow 55 = 99 e^{k' \times 39 \times 1000} \rightarrow k' =1.507 \times 10^{-5}M^{-1}s^{-1}$
answered Jul 25, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App