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What is the rate of a reaction if $[A]_o = 560\;M$, $[B]_o = 0.2\;M$, and 2nd order rate constant is $0.1\;M^{-1}s^{-1}$?

$\begin{array}{1 1} 11.2 \;Ms^{-1} \\ 5.6 \;Ms^{-1} \\ 22.4\;Ms^{-1} \\ 16.8 \;Ms^{-1} \end{array}$

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Answer: $11.2\;Ms^{-1}$
Given: $[A]_o = 560\;M$, $[B]_o = 0.2\;M$, and 2nd order rate constant is $0.1\;M^{-1}s^{-1}$
Since $[B]_0 \gt \gt [A]_0$ we can treat this as a pseudo-first order reaction.
$\Rightarrow $ Rate of the reaction $R = k'[A][B]$
$\Rightarrow R = 0.1 \times 560 \times 0.2 Ms^{-1} = 11.2\;Ms^{-1}$
answered Jul 25, 2014 by balaji.thirumalai
 

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