Chat with tutor

Ask Questions, Get Answers

Questions  >>  CBSE XI  >>  Math  >>  Linear Inequalities

Solve $24 x < 100$ when (i) x is a natural number (ii) x is an integer

1 Answer

  • Same Quantity can be added (a subtracted ) to (from ) both sides of the inequality with out changing the sign of the in equality.
  • Same positive quantities can be multiplied or divided to both side of the in equality with out changing the sign of the inequality.
  • If same negative quantity is multiplied or divided to both sides of the inequality is reversed i.e $ '>'$ sign changes to $'<' $ and $'<'$ changes $'>'$ .
Step 1:
The given in equalities
$24 x < 100$
Dividing both sides by positive number 24 we get,
$\large\frac{24x}{24} < \frac{100}{24}$
$x < \large\frac{25}{6}$
Step 2:
The number $1,2,3,$ and $4$ are the only natural number less than $ \large\frac{25}{6}$ The solution set is $ \{1,2,3,4\}$
Step 3:
The integer less than $\large\frac{25}{6}$ are $-4,-3,-2,-1,0,1,2,3,4$
The solution set is $\{.......,-4,-3,-2,-1,0,1,2,3,4,\}$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.