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# The oxidation state of Sc in $Sc_2Si_2O_7$ is

$\begin{array}{1 1}+2\\+3\\+4\\+6\end{array}$

The charge of $Si_2O_7^x$ is $Si_2O_7^x=(SiO_4^{4-})_2-O^{2-}$
$\Rightarrow Si_2O_7^{6-}$
Hence,the charge on Sc is $(6+)/2=3+$
Alternatively,$2x+2(4+)+7(-2)-0$
$\Rightarrow x=3^+$