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The treatment of $Mg_3B_2$ with acids produces

$\begin {array} {1 1} (A)\;B_2O_3 & \quad (B)\;MgB_2O_4 \\ (C)\;B_4H_{10} & \quad (D)\;MgB_4O_7 \end {array}$

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Answer : $B_4H_{10}$
The treatment of borides with acids produces boranes.
 

 

answered Jul 25, 2014 by thanvigandhi_1
edited Jul 28, 2014 by thanvigandhi_1
 
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