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# The treatment of $Mg_3B_2$ with acids produces

$\begin {array} {1 1} (A)\;B_2O_3 & \quad (B)\;MgB_2O_4 \\ (C)\;B_4H_{10} & \quad (D)\;MgB_4O_7 \end {array}$

Answer : $B_4H_{10}$