$\begin{array}{1 1} (A)\;(-3,\infty)\\(B)\;(-\infty,2]\\(C)\;(-4,\infty)\\(D)\; (-9,\infty]\end{array} $

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- Same Quantity can be added (a subtracted ) to (from ) both sides of the inequality with out changing the sign of the in equality.
- Same positive quantities can be multiplied or divided to both side of the in equality with out changing the sign of the inequality.
- If same negative quantity is multiplied or divided to both sides of the inequality is reversed i.e $ '>'$ sign changes to $'<' $ and $'<'$ changes $'>'$ .

The given inequality is $37-(3x+5) \geq 9x-8(x-3)$

=> $ 37-3x-5 \geq 9x-8x+24$

=> $ 32 -3x \geq x+24$

Adding 3x and subtracting 24 from both sides,

=> $32 -24 \geq x +3x$

=> $ 8 \geq 4x$

=> $ 2 \geq x$

Step 2:

All real number greater than or equal to 2 are solutions of the given inequality

The solution set is $(- \infty , 2]$

Hence B is the correct answer.

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