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Linear Inequalities
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Solve the given inequality and show the graph of the solution on number line: $ 3x-2 <2 x +1$
cbse
math
class11
ch6
linear-inequalities
exercise6-1
q17
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asked
Jul 26, 2014
by
meena.p
edited
Jul 28, 2014
by
meena.p
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Toolbox:
Same Quantity can be added (a subtracted ) to (from ) both sides of the inequality with out changing the sign of the in equality.
Same positive quantities can be multiplied or divided to both side of the in equality with out changing the sign of the inequality.
If same negative quantity is multiplied or divided to both sides of the inequality is reversed i.e $ '>'$ sign changes to $'<' $ and $'<'$ changes $'>'$ .
To represent solution of linear inequality involving one variable on a number line, if the inequality involves $\geq $ or $\leq$ are draw filled circle (0) on the number is included in the solution set.
If the inequality involves $'>'$ or $'<'$ we draw open circle (0) on the number line to indicate the number is excluded from the solution set.
The given inequality is $3x-2 < 2x+1$
Adding +2 and -2x on both sides of the inequality .
=> $ 3x-2x <1+2$
$x <3$
Step 2:
All numbers less than 3 from the solution set for the given inequality $(-\infty,3)$
The graphical representation on the number line is
http://clay6.com/mpaimg/cbse%20m1.jpg
answered
Jul 26, 2014
by
meena.p
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