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# Heating of $Al_2(SO_4)_3$ gives

$\begin {array} {1 1} (A)\;Al_2O_3\: and \: O_2 & \quad (B)\;Al_2O_3\: and \: SO_2 \\ (C)\;Al_2O_3\: and \: SO_3 & \quad (D)\;Al_2O_3S\: and \: O_2 \end {array}$

The reaction is $Al_2 (SO_4)_3 \rightarrow Al_2O_3+3SO_3$
$Al_2O_3\: and \: SO_3$