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Chrome alum is

$\begin {array} {1 1} (A)\;K_2SO_4.Cr_2(SO_4)_3.6H_2O \\ (B)\;K_2SO_4.Cr_2(SO_4)_3.12H_2O \\ (C)\;K_2SO_4.Cr_2(SO_4)_3.18H_2O \\ (D)\;K_2SO_4.Cr_2(SO_4)_3.24H_2O \end {array}$

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The chrome alum involves 24 water of crystallization.
$K_2SO_4.Cr_2(SO_4)_3.24H_2O $
Hence option (D) is the correct answer.
answered Jul 27, 2014 by thanvigandhi_1
edited Jul 28, 2014 by thanvigandhi_1
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