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Q)

In the reaction $H_3BO_3$$ _{\overrightarrow{375k}} A$$ _{\overrightarrow{475k}} B$$ _{\overrightarrow{red\: heat}} C$ The compounds A, B and C respectively are

$\begin {array} {1 1} (A)\;B_2O_3,H_2B_4O_7,HBO_2 \\ (B)\;B_2O_3,HBO_2, H_2B_4O_7 \\ (C)\;H_2B_4O_7,HBO_2,B_2O_3 \\ (D)\;HBO_2, H_2B_4O_7,B_2O_3 \end {array}$

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A)
Answer : $HBO_2,H_2B_4O_7,B_2O$
Option (D) is the correct answer.
The reactions are $H_3BO_4 \large\frac{-H_2O}{375k}$$HBO_2 $$_{\overrightarrow{435k}}$$H_2B_4O_7 $$_{\overrightarrow{red\: heat}}$$B_2O_3$
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