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When XeF$_4$ reacts with water, which of the following are possible product(s) that can be formed? Xe, HF, XeO$_3$, XeOF$_3$, XeO$_4$, O$_3$.

$\begin{array}{1 1} Xe, HF, XeO_3 \\Xe, HF, XeO_4 \\ HF, XeO_3, O_3 \\ Xe, HF\end{array}$
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Answer: Xe, HF, XeO$_3$
The possible reactions with water are:
XeF$_4$ + 2H$_2$O $\rightarrow$ Xe + O$_2$ + 4HF and
3XeF$_4$ + 6H$_2$O $\rightarrow$ 2XeO$_3$ + 12HF
answered Jul 27, 2014 by balaji.thirumalai
 

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