$\begin{array}{1 1} (A)\;(7,8),(7,3) \\(B)\;(3,5),(3,1) \\(C)\;(5,7),(7,9) \\(D)\;(2,3),(4,5) \end{array} $

- Same Quantity can be added (a subtracted ) to (from ) both sides of the inequality with out changing the sign of the in equality.
- Same positive quantities can be multiplied or divided to both side of the in equality with out changing the sign of the inequality.
- If same negative quantity is multiplied or divided to both sides of the inequality is reversed i.e $ '>'$ sign changes to $'<' $ and $'<'$ changes $'>'$ .

Let the two consecutive odd positive integer be $x$ and $x+2$.

Both number are smaller than 10 Therefore

$x+2 <10$

Adding $-2$ to both sides,

$=> x < 10-2$

$=> x < 8$

Also sum of the two integers is more than 11.

So, $x + x+2 > 11$

$=> 2x +2 > 11$

adding $-2$ to both sides,

$=> 2x > 11-2$

$=> 2x > 9$

Adding -2 to both sides,

$=> 2x > 11-2$

$=> 2x > 9$

Diving by 2 on both sides,

$=> x > 9/2$

$=> x > 4.5$

Step 2 :

Since x is an odd integer number greater than $4.5$ and less than 8 (from 0) x can take values 5 and 7.

Thus the required pairs are $ (5,7)$ and $(7,9)$

Hence C is the correct answer.

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