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The hybridization of I in $ICl^-_2$ is

$\begin{array}{1 1}sp\\sp^3\\d^2sp^3\\sp^3d\end{array} $

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Answer : $sp^3d$
There are $3\times 7+1=22$ valence electrons in $ICl_2^-$.These are distributed as
Due to five pairs of electrons around I,the hybridization of I will be $sp^3d$
answered Jul 29, 2014 by sreemathi.v
 
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