# The hybridization of I in $ICl^-_4$ is

$\begin{array}{1 1}sp^3\\dsp^2\\sp^3d^2\\d^2sp^3\end{array}$

Answer : $sp^3d^2$
There are $5\times 7+1=36$ valence electrons in $ICl^-_{4-}$.These are distributed as
There are six pairs of electrons around I.It hybridization will be $sp^3d^2$