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The hybridization of I in $ICl^-_4$ is

$\begin{array}{1 1}sp^3\\dsp^2\\sp^3d^2\\d^2sp^3\end{array} $

1 Answer

Answer : $sp^3d^2$
There are $5\times 7+1=36$ valence electrons in $ICl^-_{4-}$.These are distributed as
There are six pairs of electrons around I.It hybridization will be $sp^3d^2$
answered Jul 29, 2014 by sreemathi.v
 
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