The given statement is

"If all the angles of a triangle are equal then the triangle is an obtuse angled triangle."

Let $ABC$ be a triangle in which all the angles are equal to $x.$ (say)

For any $\Delta$ the sum of the angles is equal to $180^\circ$.

$\Rightarrow\:\:x+x+x=180^\circ$

$\Rightarrow\:3x=180^\circ$ or $x=60^\circ$.

$\Rightarrow\: $ All the three angles are equal to $60^\circ$.

But in an obtuse angled $\Delta$, one angle is greater than $90^\circ$.

$\therefore$ $\Delta\:ABC$ cannot be obtuse angled $\Delta.$

Hence the given statement is false.