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How many lattice points are there in one unit cell of each of the following lattice?Face-centred cubic

$\begin{array}{1 1}\text{4 atoms}\\\text{3 atoms}\\\text{2 atoms}\\\text{1 atom}\end{array} $

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Lattice points in face-centered cubic :
8 corners atoms $\times \large\frac{1}{8}$ atom per unit cell=$8\times \large\frac{1}{8}$$=1$ atom
6 face-centered atoms $\times \large\frac{1}{2}$ atom per unit cell
$\Rightarrow 6\times \large\frac{1}{6}$$=3$ atoms
$\therefore$ Total number of atoms per unit cell =4 atoms
answered Jul 29, 2014 by sreemathi.v
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