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What is the general electronic configuration of transiton elements?

$\begin {array} {1 1} (n-1) d^{1-10}ns^{1-2} \\ (n-1) d^{1-10}ns \\ n^2d^{1-10}s^{1-2}\\(n-1) d^{1-8}ns^{1-2} \end {array}$

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Answer: $(n-1) d^{1-10}ns^{1-2}$
The general electronic configuration of the d-block elements is $\text{[Inert gas]}\; (n-1)d^{1-10}n s^{1-2}$
he d-sub-shell is the penultimate (last but one) sub-shell and is denoted as (n-1) d-sub-shell. The number of s electrons may vary from one to two
The s-sub-shell in the valence shell is represented as the ns sub-shell. However, palladium (Pd) is an exception with no electron in the s-sub shell. In the periodic table, the transition metals are present in ten groups (3 to 12).
answered Jul 29, 2014 by balaji.thirumalai

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