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Non-stoichiometric cuprous oxide, $Cu_2O$ can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1. Can you account for the fact that this substance is a p-type semiconductor?

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The ratio is less than 2 : 1 in $Cu_2O$ shows that some cuprous ($Cu^+)$ ions have been replaced by $(Cu^{2+})$ ions.To maintain electrical neutrality.Every two $Cu^+$ ions will be replaced by one $Cu^{2+}$ ion.
Thereby creating a hole.As conduction will be due to these positive holes,hence it is a p-type semiconductor.
answered Jul 30, 2014 by sreemathi.v
 

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